JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 6)
A charge particle is moving in a uniform magnetic field $$(2 \hat{i}+3 \hat{j}) \,\mathrm{T}$$. If it has an acceleration of $$(\alpha \hat{i}-4 \hat{j})\, \mathrm{m} / \mathrm{s}^{2}$$, then the value of $$\alpha$$ will be :
3
6
12
2
Spiegazione
As magnetic force is perpendicular to magnetic field
So, $$\overrightarrow F $$ . $$\overrightarrow B $$ must be 0
So, 2$$\alpha$$ $$-$$ 12 = 0
$$\alpha$$ = 6